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Solving the equation 4x+2y=124x + 2y = 12

Here are two standard approaches:


1. Slope-intercept form (solving for yy):

4x+2y=122y=4x+12(Subtract 4x)y=2x+6 (Divide by 2)\begin{align*} 4x + 2y &= 12 \\ 2y &= -4x + 12 \quad \text{(Subtract $4x$)} \\ y &= -2x + 6 \quad \ \text{(Divide by 2)} \end{align*}
  • Slope: 2-2
  • Y-intercept: (0,6)(0, 6)

2. Finding intercepts

  • X-intercept (y=0y=0): 4x+2(0)=12    x=3(3,0)4x + 2(0) = 12 \implies x = 3 \quad \rightarrow (3, 0)

  • Y-intercept (x=0x=0):
    4(0)+2y=12    y=6(0,6)4(0) + 2y = 12 \implies y = 6 \quad \rightarrow (0, 6)

Graph the line through (3,0)(3, 0) and (0,6)(0, 6).


Solution Set

All real solutions lie on the line y=2x+6y = -2x + 6. Example ordered pairs:

  • When x=1x=1: y=4y=4(1,4)(1, 4)
  • When x=2x=2: y=2y=2(2,2)(2, 2)
  • When x=1x=-1: y=8y=8(1,8)(-1, 8)

❓ Let me know if you'd like help with:

  • Solving for specific values
  • Converting to other forms
  • Graphing techniques
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